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$\frac{2x^2 – 3xy – 2y^2}{4x^2 – y^2}$
Factorize numerator
2x2 - 3xy – 2y2
(2x2 + xy)(4xy – 2y2)
X(2x + y) -2y(2x + y)
= (x – 2y)(2x + y)
Factorize denominator
4x2 - y2 = (2x - y)(2x + y)
Combine numerator and denominator to get
$\frac{(x – 2y)(2x + y)}{(2x + y)(2x - y)}$ = $\frac{(x – 2y)}{(2x - y)}$
johnmulu answered the question on March 6, 2017 at 07:13
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